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Synchronizing local compiler cache.
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{"architectures": ["LlamaForCausalLM"], "attention_bias": false, "attention_dropout": 0.0, "bos_token_id": 128256, "eos_token_id": 128257, "head_dim": 64, "hidden_act": "silu", "hidden_size": 2048, "initializer_range": 0.02, "intermediate_size": 8192, "max_position_embeddings": 131072, "mlp_bias": false, "model_type": "llama", "neuron": {"compiler_version": "2.15.128.0+56dc5a86", "input_specs": {"chosen": ["<|im_start|>user\nWhat is the greatest positive integer that must divide the sum of the first ten terms of any arithmetic sequence whose terms are positive integers?<|im_end|>\n<|im_start|>assistant\nI know that the sum of the first n terms of an arithmetic sequence is given by the formula S_n = n(a_1 + a_n) / 2, where a_1 is the first term and a_n is the nth term.\nSo, to find the sum of the first ten terms, I can plug in n = 10 and get S_10 = 10(a_1 + a_10) / 2.\nI can simplify this to S_10 = 5(a_1 + a_10).\n[*. So, the sum of the first ten terms is always a multiple of 5, regardless of the values of a_1 and a_10.\nTherefore, the greatest positive integer that must divide S_10 is 5.\n# Answer\n\n5<|im_end|>\n"], "chosen_attention_mask": [1, 512], "chosen_input_ids": [1, 512], "chosen_labels": [1, 512], "prompt": ["What is the greatest positive integer that must divide the sum of the first ten terms of any arithmetic sequence whose terms are positive integers?"], "prompt_attention_mask": [1, 512], "prompt_input_ids": [1, 512], "question": ["What is the greatest positive integer that must divide the sum of the first ten terms of any arithmetic sequence whose terms are positive integers?"], "rejected": ["<|im_start|>user\nWhat is the greatest positive integer that must divide the sum of the first ten terms of any arithmetic sequence whose terms are positive integers?<|im_end|>\n<|im_start|>assistant\nThe first 10 terms of any arithmetic sequence can be represented as $x$, $x+c$, $x+2c$, $\\ldots x+9c$, where $x$ is the first term and $c$ is the constant difference between each consecutive term. So, the sum of all of these terms will include $10x$ and $(1+2+\\ldots+9)c$, which equals $45c$. As a result, the sum of all the terms is $10x+45c$ and the greatest number we can factor out is $\\boxed{5}$, where we end up with $5(2x+9c)$.<|im_end|>\n"], "rejected_attention_mask": [1, 512], "rejected_input_ids": [1, 512], "rejected_labels": [1, 512], "source": ["prm_dpo_pairs"]}, "model_class": "PeftModelForCausalLM", "num_neuron_cores_per_node": 2, "pipeline_parallel_size": 1, "precision": "bfloat16", "tensor_parallel_size": 1, "training": true}, "num_attention_heads": 32, "num_hidden_layers": 16, "num_key_value_heads": 8, "pad_token_id": 128257, "pretraining_tp": 1, "rms_norm_eps": 1e-05, "rope_scaling": {"factor": 32.0, "high_freq_factor": 4.0, "low_freq_factor": 1.0, "original_max_position_embeddings": 8192, "rope_type": "llama3"}, "rope_theta": 500000.0, "tie_word_embeddings": true, "torch_dtype": "bfloat16", "use_cache": true, "vocab_size": 128258}