neuronxcc-2.15.128.0+56dc5a86/0_REGISTRY/0.0.25.dev0/training/llama/meta-llama/Llama-3.2-1B-Instruct/a42def2dae7c87109a7c.json

{"architectures": ["LlamaForCausalLM"], "attention_bias": false, "attention_dropout": 0.0, "bos_token_id": 128256, "eos_token_id": 128257, "head_dim": 64, "hidden_act": "silu", "hidden_size": 2048, "initializer_range": 0.02, "intermediate_size": 8192, "max_position_embeddings": 131072, "mlp_bias": false, "model_type": "llama", "neuron": {"compiler_version": "2.15.128.0+56dc5a86", "input_specs": {"chosen": ["<|im_start|>user\nCreate a solution in Lua for the following task: Identity matrix\n\nBuild an identity matrix of a size known at run-time.\n\nAn \"identity matrix\" is a square matrix of size \"n x n\", where the diagonal elements are all 1s (ones), and all the other elements are all 0s (zeroes).\n\nI_n = [\n  [1, 0, 0, ..., 0],\n  [0, 1, 0, ..., 0],\n  [0, 0, 1, ..., 0],\n  ...,\n  [0, 0, 0, ..., 1]\n]\n\nRelated tasks:\n- Spiral matrix\n- Zig-zag matrix\n- Ulam spiral (for primes) PLAINFORMAT\n<|im_end|>\n<|im_start|>assistant\nfunction identity_matrix (size)\n        local m = {}\n        for i = 1, size do\n                m[i] = {}\n                for j = 1, size do\n                        m[i][j] = i == j and 1 or 0\n                end\n        end\n        return m\nend\n\nfunction print_matrix (m)\n        for i = 1, #m do\n                print(table.concat(m[i], \" \"))\n        end\nend\n\nprint_matrix(identity_matrix(5))<|im_end|>\n<|im_start|>user\nHow would you modify the given Lua function to generate a diagonal matrix, where the diagonal elements are not 1 but an arbitrary number provided by the user?<|im_end|>\n<|im_start|>assistant\nYou can modify the `identity_matrix` function to accept an additional parameter for the diagonal value. Here's how you can do it:\n\n```lua\nfunction diagonal_matrix (size, diagonal)\n        local m = {}\n        for i = 1, size do\n                m[i] = {}\n                for j = 1, size do\n                        m[i][j] = i == j and diagonal or 0\n                end\n        end\n        return m\nend\n\nfunction print_matrix (m)\n        for i = 1, #m do\n                print(table.concat(m[i], \" \"))\n        end\nend\n\nprint_matrix(diagonal_matrix(5, 3))\n```\n\nIn this version of the function, the diagonal elements of the matrix will be the value of the `diagonal` parameter. If you call `diagonal_matrix(5, 3)`, it will create a 5x5 matrix with 3s on the diagonal and 0s everywhere else.<|im_end|>\n<|im_start|>user\nCan the modified function handle non-integer diagonal values? If not, how would you adjust it to do so?<|im_end|>\n<|im_start|>assistant\nThe modified function will indeed handle non-integer diagonal values since only the condition `i == j and diagonal` or `i == j and diagonal or 0` depends on the value of `diagonal`. As long as it's any applicable number for the given task, the function will work as expected. The change needed is primarily in the function description and example to showcase using non-integer values. Here's an adjusted description and example for the `diagonal_matrix` function:\n\n```lua\nfunction diagonal_matrix (size, diagonal)\n        local m = {}\n        for i = 1, size do\n                m[i] = {}\n                for j = 1, size do\n                        m[i][j] = i == j and diagonal or 0\n                end\n        end\n        return m\nend\n\nfunction print_matrix (m)\n        for i = 1, #m do\n                print(table.concat(m[i], \" \"))\n        end\nend\n\n-- Create a 3x3 matrix with 2.5 as the diagonal value:\nprint_matrix(diagonal_matrix(3, 2.5))\n```\n\nNow, when you call `diagonal_matrix(3, 2.5)`, it will create a 3x3 matrix with 2.5s on the diagonal and 0s elsewhere. The user has full flexibility to use any number as the value for the diagonal when calling this function. <|im_end|>\n"], "chosen_attention_mask": [1, 512], "chosen_input_ids": [1, 512], "chosen_labels": [1, 512], "prompt": ["Create a solution in Lua for the following task: Identity matrix\n\nBuild an identity matrix of a size known at run-time.\n\nAn \"identity matrix\" is a square matrix of size \"n x n\", where the diagonal elements are all 1s (ones), and all the other elements are all 0s (zeroes).\n\nI_n = [\n  [1, 0, 0, ..., 0],\n  [0, 1, 0, ..., 0],\n  [0, 0, 1, ..., 0],\n  ...,\n  [0, 0, 0, ..., 1]\n]\n\nRelated tasks:\n- Spiral matrix\n- Zig-zag matrix\n- Ulam spiral (for primes) PLAINFORMAT\n"], "prompt_attention_mask": [1, 512], "prompt_input_ids": [1, 512], "question": ["Create a solution in Lua for the following task: Identity matrix\n\nBuild an identity matrix of a size known at run-time.\n\nAn \"identity matrix\" is a square matrix of size \"n x n\", where the diagonal elements are all 1s (ones), and all the other elements are all 0s (zeroes).\n\nI_n = [\n  [1, 0, 0, ..., 0],\n  [0, 1, 0, ..., 0],\n  [0, 0, 1, ..., 0],\n  ...,\n  [0, 0, 0, ..., 1]\n]\n\nRelated tasks:\n- Spiral matrix\n- Zig-zag matrix\n- Ulam spiral (for primes) PLAINFORMAT\n"], "rejected": ["<|im_start|>user\nCreate a solution in Lua for the following task: Identity matrix\n\nBuild an identity matrix of a size known at run-time.\n\nAn \"identity matrix\" is a square matrix of size \"n x n\", where the diagonal elements are all 1s (ones), and all the other elements are all 0s (zeroes).\n\nI_n = [\n  [1, 0, 0, ..., 0],\n  [0, 1, 0, ..., 0],\n  [0, 0, 1, ..., 0],\n  ...,\n  [0, 0, 0, ..., 1]\n]\n\nRelated tasks:\n- Spiral matrix\n- Zig-zag matrix\n- Ulam spiral (for primes) PLAINFORMAT\n<|im_end|>\n<|im_start|>assistant\nfunction identity_matrix (size)\n        local m = {}\n        for i = 1, size do\n                m[i] = {}\n                for j = 1, size do\n                        m[i][j] = i == j and 1 or 0\n                end\n        end\n        return m\nend\n\nfunction print_matrix (m)\n        for i = 1, #m do\n                print(table.concat(m[i], \" \"))\n        end\nend\n\nprint_matrix(identity_matrix(5))<|im_end|>\n<|im_start|>user\nHow would you modify the given Lua function to generate a diagonal matrix, where the diagonal elements are not 1 but an arbitrary number provided by the user?<|im_end|>\n<|im_start|>assistant\nYou can modify the `identity_matrix` function to accept an additional parameter for the diagonal value. Here's how you can do it:\n\n```lua\nfunction diagonal_matrix (size, diagonal)\n        local m = {}\n        for i = 1, size do\n                m[i] = {}\n                for j = 1, size do\n                        m[i][j] = i == j and diagonal or 0\n                end\n        end\n        return m\nend\n\nfunction print_matrix (m)\n        for i = 1, #m do\n                print(table.concat(m[i], \" \"))\n        end\nend\n\nprint_matrix(diagonal_matrix(5, 3))\n```\n\nIn this version of the function, the diagonal elements of the matrix will be the value of the `diagonal` parameter. If you call `diagonal_matrix(5, 3)`, it will create a 5x5 matrix with 3s on the diagonal and 0s everywhere else.<|im_end|>\n<|im_start|>user\nCan the modified function handle non-integer diagonal values? If not, how would you adjust it to do so?<|im_end|>\n<|im_start|>assistant\nThe current implementation of `diagonal_matrix` expects the diagonal values to be integers, as it uses the `i == j` operator to check if a position is on the diagonal. To handle non-integer diagonal values, you would need to modify how the function checks for diagonal positions.\n\n Here's an updated implementation that uses `math.abs()` function to find the absolute difference between row and column indices, to determine if a position is on the diagonal:\n\n```lua\nfunction diagonal_matrix (size, diagonal)\n        local m = {}\n        for I = 1, size do\n                m[i] = {}\n                for j = 1, size do\n                        local d = math.abs(i - j)\n                        m[i][j] = d == 0 and diagonal or 0\n                end\n        end\n        return m\nend\n\nfunction print_matrix (m)\n        for I = 1, #m do\n                print(table.concat(m[i], \" \"))\n        end\nend\n\n-- Example usage\nprint_matrix(diagonal_matrix(5, 3.14))\n```\n\nNow, calling `diagonal_matrix(5, 3.14)` will create a 5x5 matrix with the elements on the main diagonal set to 3.14, and all other elements set to 0.<|im_end|>\n"], "rejected_attention_mask": [1, 512], "rejected_input_ids": [1, 512], "rejected_labels": [1, 512], "source": ["Know-Logic"]}, "model_class": "PeftModelForCausalLM", "num_neuron_cores_per_node": 2, "pipeline_parallel_size": 1, "precision": "bfloat16", "tensor_parallel_size": 1, "training": true}, "num_attention_heads": 32, "num_hidden_layers": 16, "num_key_value_heads": 8, "pad_token_id": 128257, "pretraining_tp": 1, "rms_norm_eps": 1e-05, "rope_scaling": {"factor": 32.0, "high_freq_factor": 4.0, "low_freq_factor": 1.0, "original_max_position_embeddings": 8192, "rope_type": "llama3"}, "rope_theta": 500000.0, "tie_word_embeddings": true, "torch_dtype": "bfloat16", "use_cache": true, "vocab_size": 128258}